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120d^2=1.89
We move all terms to the left:
120d^2-(1.89)=0
We add all the numbers together, and all the variables
120d^2-1.89=0
a = 120; b = 0; c = -1.89;
Δ = b2-4ac
Δ = 02-4·120·(-1.89)
Δ = 907.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{907.2}}{2*120}=\frac{0-\sqrt{907.2}}{240} =-\frac{\sqrt{}}{240} $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{907.2}}{2*120}=\frac{0+\sqrt{907.2}}{240} =\frac{\sqrt{}}{240} $
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